Tiny Star

martes, 14 de octubre de 2014

1.2 Ejercicios

PROBLEMA 5

Estiraje por desarrollos.
 N1= (2800)(28)(23)(50)(50)(27) / (15)841)(23)(80)(30)= 3585 rpm
D n1= π x 3” x 3585= 33787”/min
N2= (2800)828) / (15)=5226 rpm
D n2= π x 1.5” x 5226= 24,626”/min
N3= (28009(28)823) / (15)(41)= 2,932 rpm
D n3= π x 2” x 2,932= 18,422”/min
N4= (2800)828)(23)(25) / (15)(41)(14)= 5235.77 rpm
D n4= 1.5” x π x 5235.77= 24,673.04”/min
N5= (2800)(28)823)813) / (15)(41)(27)= 1444 rpm
D n5= π x 5” x 1411= 22,163”/min

Total
Et= D cilindro productor/ D cilindro alimentador
Et=22,163”/min / 33787”/min= 0.65

Parcial
1-2= 24,626”/min / 33787”/min= 0.72
2-3= 18,422”/min / 24,626”/min= 0.74
3-4= 24,673.04”/min / 18,422”/min= 1.33
4-5= 22,163”/min /  24,673.04”/min= 0.89
Et= 0.72 x 0.74 x 1.33 x 0.89= 0.63

Estiraje por relación de engranes.
Total
Et= π x ф productor  x n productor / π x ф alimentador  x n alimentador
Et= (5”)(30)(80)(23)(13) / (3”)(27)(50)(50)(27)= 0.65
Parcial
1-2= (1.5”)(30)(80)823)(41) / (3”)(27)(50)850)(23)= 0.72
2-3= (2”)(23) / (1.5”)(41)= 0.74
3-4= (1.5”)(25) / (2”)(14)= 1.33
4-5= (5”)(14)(13)/(1.5”)(25)(27)=0.89
Et= 0.72 x 0.74 x 1.33 x 0.89= 0.63

PROBLEMA 6

Estiraje por desarrollos.
N1= (7000)(32) / (12)= 18,666 rpm
D n1= π x 2.125” x 18,666= 124,612”/min
N2= (7000)(32) / (31)= 7,225 rpm
D n2= π x 2.25” x 7,225= 51,070”/min
N3= 7000rpm
D n3= π x 1.33” x 7000= 29,248”min
N4= (7000)(57) / (72)= 5,541 rpm
D n4= π x 5,541 x 2”= 34,815”/min
N5= (700)(57)(20)(19)(28)825) / (72)(16)835)(59)835)= 1274 rpm
D n5= π x 4.7512 x 1274= 19,011”/min
 
Total
Et= D cilindro productor/ D cilindro alimentador
Et= 19,011”/min / 124,612”/min= 0.15
Parcial
1-2= 51,070”/min / 124,612”/min= 0.40
2-3= 29,248”min / 51,070”/min= 0.57
3-4= 34,815”/min / 29,248”min= 1.19
4-5= 19,011”/min / 34,815”/min= 0.54
Et= 0.40 x 0.57 x 1.19 x 0.54= 0.14

Estiraje por relación de engranes.
Total
Et= π x ф productor  x n productor / π x ф alimentador  x n alimentador
Et=(4.75”)(12)(57)820)(19)(289825) / (2.125”)(32)(72)(16)(35)(59)(35)= 0.15

Parcial
1-2= (2.25”)(12) / (2.125”)(31)= 0.40
2-3= (1.33”)(31) / (2.25”)(32)= 0.57
3-4= (2”)(57)/ (1.33”)(72)= 1.19
4-5= (4.75”)(20)(19)(28)(25) / (2”)(16)(35)(59)(35)= 0.54
Et= 0.40 x 0.57 x 1.19 x 0.54= 0.14

PROBLEMA 7

Estiraje por desarrollos
N1= (3200)(45)(12) / (30)(22)= 2618 rpm
D n1= π x 2618 x 2.5”= 20,561”/min
N2= (3200)(45)(12)(28) / (30)(22)(70)= 1047 rpm
D n2= π x 1047 x 1.125”= 3700”/min
N4= (3200)(74)(84) / (47)(22)= 19,237 rpm
D n4= π x 2.25” x 19,237= 135,978”/min
N5= (3200)(65) / (24)= 8666 rpm
D n5= π x 8666 x 4.75”= 129,318”/min
N7= (3200)(65) / (32)= 6500 rpm
D n7= π x 6500 x 4.5”= 91,891”/min
N8= (3200)(45) / (70)= 2057 rpm
D n8= π x 2057 x 6”= 38,773”/min

Total
Et= D cilindro productor/ D cilindro alimentador
Et=38,773”/min / 20,561”/min= 1.88

Parcial
1-2= 3700”/min / 20,561”/min= 0.17
2-4= 135,978”/min / 3700”/min= 36.75
4-5= 129,318”/min / 135,978”/min= 0.95
5-7= 91,891”/min  / 129,318”/min =0.71
7-8= 38,773”/min / 91,891”/min= 0.42
Et= 0.17 x 36.73 x 0.95 x 0.71 x 0.42= 1.76

Estiraje por relación de engranes
Total
Et= π x ф productor  x n productor / π x ф alimentador  x n alimentador
Et= (6”)(32)(45) / (2.5”)(12)(70)= 1.8

Parcial
1-2= (1.125”)(28) / (2.5”)(70)= 0.18
2-4= (2.25”)(70)(22)(30)(74)(84) / (1.125”)(28)(12)845)(47)(22)= 36
4-5= (4.75”)(22)(47)(65) / (2.25”)(84)(74)(24)= 0.95
5-7= (4.5”)(24) / (4.75”)(32)= 0.71
7-8= (6”)(32)(45) / (4.5”)(65)(70)= 1.83

PROBLEMA 8

Estiraje por desarrollos.
N1= (1800)(27)(19)(25)(20)(30)(72)(20) / (160)(40)(80)(15)(55)(30)(120)= 13 rpm
D n1= π x 13 x 1.125”= 45”/min
N2= (1800)(27)(19)(25)(20) / (160)(40)(80)(15)= 60 rpm
D n2= π x 60 x 5.125”= 966”/min
N3= (1800)(27)(19) / (160)(58)= 99 rpm
D n3= π x pp x 1.33= 413”/min
N4= (1800)(27)(19)(90) / (160)(58)(60)= 149 rpm
D n4= π x 149 x 1.25”= 585”/min

Total
Et= D cilindro productor/ D cilindro alimentador
Et=585”/min / 45”/min= 13

Parcial
1-2= 966”/min / 45”/min= 21.46
2-3= 413”/min / 966”/min= 0.42
3-4= 585”/min / 413”/min= 1.41
Et= 21.46 x 0.42 x 1.41= 11.98

Estiraje por relación de engranes.
Total
Et= π x ф productor  x n productor / π x ф alimentador  x n alimentador
Et= (1.25”)(120)(30)(55)(15)(80)(40)(90) / (1.125”)(20)(72)(30)(20)(25)(58)(60)= 12.6

Parcial
1-2= (5.125”)(120)(30)(55) / ((1.125”)(20)(72)(30)= 21.47
2-3= (1.33”)(15)(80)(40) / (5.125”)(20)(25)(58)= 0.42
3-4= (1.25)(90) / (1.33”)(60)= 1.40
Et= 21.4 x 0.4 x 1.4= 11.98